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	<title>Comments on: Told You So</title>
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	<link>http://selenianboondocks.com/2009/07/told-you-so/</link>
	<description>Random Musings from the Warped Minds of Jonathan Goff, Ken Murphy, John Hare, and Kirk Sorensen</description>
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		<title>By: john hare</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5249</link>
		<dc:creator>john hare</dc:creator>
		<pubDate>Thu, 23 Jul 2009 09:22:25 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5249</guid>
		<description>Fiddling around has started before the parts left the machine shop. Terry spun the turbine up to (Terrys&#039; estimate) 30,000-60,000 rpms dry with shop air. I increased exhaust ports from 1 to 6 spaced under the turbine perimeter. Based on the air required to do this, I changed the air feed to the 1&quot; used on the jackhammer air compressors rather than shop air.  

The rpm estimate is based on his experience that I have no intuitive feel for, so I&#039;m a bit of a sceptic. If it actually reaches those rpms in loaded use, it corresponds to pressures of 300-1,200 psi, given reasonable pressure recovery. I&#039;m starting to think it possible that the unit will actually push water up to over 75 psi. If it does, then it seems that the air mass will be less than the water mass being pumped.</description>
		<content:encoded><![CDATA[<p>Fiddling around has started before the parts left the machine shop. Terry spun the turbine up to (Terrys&#8217; estimate) 30,000-60,000 rpms dry with shop air. I increased exhaust ports from 1 to 6 spaced under the turbine perimeter. Based on the air required to do this, I changed the air feed to the 1&#8243; used on the jackhammer air compressors rather than shop air.  </p>
<p>The rpm estimate is based on his experience that I have no intuitive feel for, so I&#8217;m a bit of a sceptic. If it actually reaches those rpms in loaded use, it corresponds to pressures of 300-1,200 psi, given reasonable pressure recovery. I&#8217;m starting to think it possible that the unit will actually push water up to over 75 psi. If it does, then it seems that the air mass will be less than the water mass being pumped.</p>
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		<title>By: john hare</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5220</link>
		<dc:creator>john hare</dc:creator>
		<pubDate>Sun, 19 Jul 2009 17:36:14 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5220</guid>
		<description>Kewl. After my initial attempt fails I can use a plastic shrink ring around the turbine blades to get those results. 

Of course I am going to blast straight shop air through a nozzle one time also.

I think I am going to get fair entertainment value for my money.</description>
		<content:encoded><![CDATA[<p>Kewl. After my initial attempt fails I can use a plastic shrink ring around the turbine blades to get those results. </p>
<p>Of course I am going to blast straight shop air through a nozzle one time also.</p>
<p>I think I am going to get fair entertainment value for my money.</p>
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		<title>By: Eric.M.Collins</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5218</link>
		<dc:creator>Eric.M.Collins</dc:creator>
		<pubDate>Sun, 19 Jul 2009 17:00:34 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5218</guid>
		<description>Well sorry about that failed second attempt.  For what it&#039;s worth, I&#039;ve been able to post the diagram over at my blog (&lt;a href=&quot;http://spaceflightsandbox.blogspot.com/2009/07/turbo-pump-ascii-art.html&quot; rel=&quot;nofollow&quot;&gt;Turbo pump ASCII art&lt;/a&gt; - &lt;a href=&quot;http://spaceflightsandbox.blogspot.com/&quot; rel=&quot;nofollow&quot;&gt;Spaceflight Sandbox&lt;/a&gt;).</description>
		<content:encoded><![CDATA[<p>Well sorry about that failed second attempt.  For what it&#8217;s worth, I&#8217;ve been able to post the diagram over at my blog (<a href="http://spaceflightsandbox.blogspot.com/2009/07/turbo-pump-ascii-art.html" rel="nofollow">Turbo pump ASCII art</a> &#8211; <a href="http://spaceflightsandbox.blogspot.com/" rel="nofollow">Spaceflight Sandbox</a>).</p>
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		<title>By: Eric.M.Collins</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5216</link>
		<dc:creator>Eric.M.Collins</dc:creator>
		<pubDate>Sun, 19 Jul 2009 13:51:33 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5216</guid>
		<description>Ack.. I forget how much the blogger reply window mangles plain text.  None of the spacing was kept in my ASCII art drawing.  Let&#039;s try this:

&#124;&#124;^                         ^&#124;&#124;
&#124;&#124;  __       _____       __  &#124;&#124;
&#124;&#124;^&#124;__&#124;  V  &#124;_____&#124;  V  &#124;__&#124;^&#124;&#124;
&#124;&#124;  &#124;&#124;
&#124;&#124;____&#124;  V   _&#124;^&#124;_   V  &#124;____&#124;&#124;
&#124;_____&#124;     &#124;_&#124; &#124;_&#124;     &#124;_____&#124;
         V    &#124;^&#124;    V         


If this doesn&#039;t look good either, then feel free to delete this comment.</description>
		<content:encoded><![CDATA[<p>Ack.. I forget how much the blogger reply window mangles plain text.  None of the spacing was kept in my ASCII art drawing.  Let&#8217;s try this:</p>
<p>||^                         ^||<br />
||  __       _____       __  ||<br />
||^|__|  V  |_____|  V  |__|^||<br />
||  ||<br />
||____|  V   _|^|_   V  |____||<br />
|_____|     |_| |_|     |_____|<br />
         V    |^|    V         </p>
<p>If this doesn&#8217;t look good either, then feel free to delete this comment.</p>
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		<title>By: john hare</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5212</link>
		<dc:creator>john hare</dc:creator>
		<pubDate>Sun, 19 Jul 2009 09:42:03 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5212</guid>
		<description>I expect to moderate the chamber air pressure to various values below the 125psi available. The actual pressure observed in the chamber while it is pumping water into the chamber will give the reading on pump delivered pressure. 

33,900 rpm is fairly low compared to some of the RC jets out there. I think they use real bearings and not a bushing oiled before each test.

This rig will be cheap enough to play with that I expect to do a lot of fiddling (HH) in the manner suggested (Eric) to get any useful information. I think getting multiple &quot;I told you so&quot; is in my future.</description>
		<content:encoded><![CDATA[<p>I expect to moderate the chamber air pressure to various values below the 125psi available. The actual pressure observed in the chamber while it is pumping water into the chamber will give the reading on pump delivered pressure. </p>
<p>33,900 rpm is fairly low compared to some of the RC jets out there. I think they use real bearings and not a bushing oiled before each test.</p>
<p>This rig will be cheap enough to play with that I expect to do a lot of fiddling (HH) in the manner suggested (Eric) to get any useful information. I think getting multiple &#8220;I told you so&#8221; is in my future.</p>
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		<title>By: MG</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5211</link>
		<dc:creator>MG</dc:creator>
		<pubDate>Sun, 19 Jul 2009 08:21:43 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5211</guid>
		<description>Ok, before I get a few hours sleep, here is a quick and dirty energy analysis:

Delta P = rho v^2 / 2g  [Bernoulli, applied to water in turbine blade]

Set Delta P to 4 bar ~ 60 psi ~ 400kPa

rho = 1000 kg/m3
g = 9.817 m/s2
then
v~88.6 m/s

v = omega *r; r~.025m

Omega = 3544 radians / s = 33900 RPM

Which seems a bit high.</description>
		<content:encoded><![CDATA[<p>Ok, before I get a few hours sleep, here is a quick and dirty energy analysis:</p>
<p>Delta P = rho v^2 / 2g  [Bernoulli, applied to water in turbine blade]</p>
<p>Set Delta P to 4 bar ~ 60 psi ~ 400kPa</p>
<p>rho = 1000 kg/m3<br />
g = 9.817 m/s2<br />
then<br />
v~88.6 m/s</p>
<p>v = omega *r; r~.025m</p>
<p>Omega = 3544 radians / s = 33900 RPM</p>
<p>Which seems a bit high.</p>
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		<title>By: john hare</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5209</link>
		<dc:creator>john hare</dc:creator>
		<pubDate>Sat, 18 Jul 2009 21:47:39 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5209</guid>
		<description>The machine shop is Terry Lesnet in Lakeland Fl. Older equipment and  no CNC or CADCAM. We&#039;ve done business off and on for years. It will be a under a grand for everything. He said he would treat me right on the bill, and always has. The brighter side of cost plus.</description>
		<content:encoded><![CDATA[<p>The machine shop is Terry Lesnet in Lakeland Fl. Older equipment and  no CNC or CADCAM. We&#8217;ve done business off and on for years. It will be a under a grand for everything. He said he would treat me right on the bill, and always has. The brighter side of cost plus.</p>
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		<title>By: MG</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5203</link>
		<dc:creator>MG</dc:creator>
		<pubDate>Sat, 18 Jul 2009 15:02:39 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5203</guid>
		<description>Ah.  The sentence about 125 psi air pumping water into the test chamber confused me.

You will get *some* pumping action.  I have to go to the NewSpace 2009 opening talk, but the relevant hurdle is whether you will get enough power out of the turbine to elevate the pressure of the water at the blade exit above the pressure of the air at the blade exit.

BTW, do you mind my asking which machine shop, and how much they charge for machinining the turbine?</description>
		<content:encoded><![CDATA[<p>Ah.  The sentence about 125 psi air pumping water into the test chamber confused me.</p>
<p>You will get *some* pumping action.  I have to go to the NewSpace 2009 opening talk, but the relevant hurdle is whether you will get enough power out of the turbine to elevate the pressure of the water at the blade exit above the pressure of the air at the blade exit.</p>
<p>BTW, do you mind my asking which machine shop, and how much they charge for machinining the turbine?</p>
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		<title>By: Eric.M.Collins</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5201</link>
		<dc:creator>Eric.M.Collins</dc:creator>
		<pubDate>Sat, 18 Jul 2009 11:21:35 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5201</guid>
		<description>My prediction is that you will not get nearly as good of performance out of your turbine blades as what you are expecting; at least, not with this configuration.  The pump will work, more or less, as you expect, for the a given amount of RPMs that you are able to induce (either through the turbine blades or other means).

As I have mentioned before, I have no turbo-machinery experience, but I can see a couple of potential problems with this design just by looking at it.

First of all, by your own numbers you are attempting to inject water at a lower pressure (50-75 psi) than that of the chamber (125 psi).  Unless you mean 50-75 psi above chamber pressure, I think you may have a problem coaxing the water out of the pump.

Secondly, as Habitat Hermit noted, you are severely restricting the amount of useful surface area where momentum may be imparted to the blades.  Also, I think your high-pressure air will escape around the ends of the blades just as much as through them.

You may need to design a separate chamber for the turbo-pump that will allow you to isolate the flow paths of your shop air and your injected water.  Perhaps something like this may work: (If you can&#039;t make this out, try copy/pasting it into a fixed width text editor, like notepad.)

&#124;&#124;^                         ^&#124;&#124;
&#124;&#124;  __       _____       __  &#124;&#124;
&#124;&#124;^&#124;__&#124;  V  &#124;_____&#124;  V  &#124;__&#124;^&#124;&#124;
&#124;&#124;  &#124;&#124;
&#124;&#124;____&#124;  V   _&#124;^&#124;_   V  &#124;____&#124;&#124;
&#124;_____&#124;     &#124;_&#124; &#124;_&#124;     &#124;_____&#124;
         V    &#124;^&#124;    V         

The trick here is to prevent, as much as possible, the leakage of the high-pressure gasses from the main chamber into the pump injection chamber through the turbine.  This may require the use of a solid ring around the outer edge of the turbine blade (with injector holes appropriately located).  For the outlet of the main chamber to the turbine blades, expose as much of the turbine&#039;s surface area as possible.</description>
		<content:encoded><![CDATA[<p>My prediction is that you will not get nearly as good of performance out of your turbine blades as what you are expecting; at least, not with this configuration.  The pump will work, more or less, as you expect, for the a given amount of RPMs that you are able to induce (either through the turbine blades or other means).</p>
<p>As I have mentioned before, I have no turbo-machinery experience, but I can see a couple of potential problems with this design just by looking at it.</p>
<p>First of all, by your own numbers you are attempting to inject water at a lower pressure (50-75 psi) than that of the chamber (125 psi).  Unless you mean 50-75 psi above chamber pressure, I think you may have a problem coaxing the water out of the pump.</p>
<p>Secondly, as Habitat Hermit noted, you are severely restricting the amount of useful surface area where momentum may be imparted to the blades.  Also, I think your high-pressure air will escape around the ends of the blades just as much as through them.</p>
<p>You may need to design a separate chamber for the turbo-pump that will allow you to isolate the flow paths of your shop air and your injected water.  Perhaps something like this may work: (If you can&#8217;t make this out, try copy/pasting it into a fixed width text editor, like notepad.)</p>
<p>||^                         ^||<br />
||  __       _____       __  ||<br />
||^|__|  V  |_____|  V  |__|^||<br />
||  ||<br />
||____|  V   _|^|_   V  |____||<br />
|_____|     |_| |_|     |_____|<br />
         V    |^|    V         </p>
<p>The trick here is to prevent, as much as possible, the leakage of the high-pressure gasses from the main chamber into the pump injection chamber through the turbine.  This may require the use of a solid ring around the outer edge of the turbine blade (with injector holes appropriately located).  For the outlet of the main chamber to the turbine blades, expose as much of the turbine&#8217;s surface area as possible.</p>
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	<item>
		<title>By: john hare</title>
		<link>http://selenianboondocks.com/2009/07/told-you-so/comment-page-1/#comment-5199</link>
		<dc:creator>john hare</dc:creator>
		<pubDate>Sat, 18 Jul 2009 10:08:28 +0000</pubDate>
		<guid isPermaLink="false">http://selenianboondocks.com/?p=1096#comment-5199</guid>
		<description>The 125 psi air is diffused through the top and powers the turbine on the way out the exhaust port. The water is pumped through the ports in the turbine blades into the chamber. The only thing that will force the water into the chamber is the centrifugal pumping action. The back pressure in the chamber will define the success or failure of the pumping action. As HH suggests, if the air is exhausting back through the water port, it didn&#039;t work.</description>
		<content:encoded><![CDATA[<p>The 125 psi air is diffused through the top and powers the turbine on the way out the exhaust port. The water is pumped through the ports in the turbine blades into the chamber. The only thing that will force the water into the chamber is the centrifugal pumping action. The back pressure in the chamber will define the success or failure of the pumping action. As HH suggests, if the air is exhausting back through the water port, it didn&#8217;t work.</p>
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